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2 years ago

(Ill give brainliest)

Mathematics

1 answer:

Anna007 [38]2 years ago

3 0

Answer:

522

Step-by-step explanation:

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|−9| − |−5| i hate next gen but help pls

Setler79 [48]

Answer:

Step-by-step explanation:

$\mathrm{-9 = 9, -5 = 5,\:because\:they\:are\:in\:absolute\:value}\\9 - 5 = 4$

8 0

1 year ago

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What is an equation that passes through (18,2) and is parallel to 3y-x=-12

MrRa [10]

3(2)-18=-12
6-18 = -12
-12 = -12

5 0

3 years ago

It took Marjorie 15 minutes to drive from her house to her daughter's school. If they school was 4 miles away from her house, wh

notka56 [123]

The answer would be 3.75 miles por minute

8 0

3 years ago

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Express in exponential form. log3 27 = 3

ollegr [7]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~

How you right ANY log in Exponential form is like this:

Log_x Z = y

x^y = Z

So...

Log_3 27 = 3

3^3 = 27 would be your answer...

4 0

3 years ago

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The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amo

Aloiza [94]

Answer:

$a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]$

Step-by-step explanation:

a. -Given that:

$n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64$

#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:

$\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03$

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator, $\bar x_m-\bar x_f$ is calculated by the following following:

$\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

-And the margin of error, E at a 99% confidence can be calculated as:

$E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416$

Hence, the margin of error is 15.7416

c. The estimator confidence interval is calculated using the following formula:

$\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:

$CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]$

Hence, the 99% confidence interval is [51.2884,82.7716]

7 0

3 years ago