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astra-53 [7]
3 years ago
10

Can someone pleasee help me with this asap!! Im struggling

Chemistry
1 answer:
Alex777 [14]3 years ago
5 0

4a. D - The last number in the configuration represents the group, in this case 3, and the number of shells represent the period, which is also 3.

4bi. Rubidium metal reacts very rapidly with water to form a colourless solution of rubidium hydroxide (RbOH) and hydrogen gas (H2). The resulting solution is basic because of the dissolved hydroxide. The reaction is very exothermic and explosive.

4bii. Lithium is smaller in size than potassium . so valence electrons are more tightly held in Li than K. Due to larger size of K the valence electrons are loosely held and easy to remove the electron from K. Hence K is more reactive.

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A neutral atom in its ground state contains 28 electrons. this element is considered a ________ element, and has _______ electro
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l is azimuthal quantum number, l = 2 describes d orbital. There is eight electrons in 3d orbital.
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How many moles are equal to 12.65 grams of Al2(SO4)3?
____ [38]

Answer:

0.03697 mol Al₂(SO₄)₃

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

12.65 g Al₂(SO₄)₃

<u>Step 2: Identify Conversions</u>

Molar Mass of Al - 26.98 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol

<u>Step 3: Convert</u>

<u />12.65 \ g \ Al_2(SO_4)_3(\frac{1 \ mol \ Al_2(SO_4)_3}{342.17 \ g \ Al_2(SO_4)_3} ) = 0.03697 mol Al₂(SO₄)₃

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

We already have 4 sig figs in the final answer, so no need to round.

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