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gizmo_the_mogwai [7]
3 years ago
9

What is pH?

Chemistry
1 answer:
galben [10]3 years ago
8 0
It's B. the positive logariuthm of the hydrogen ion concentra<span>tion</span>
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Which of the following naming rules would apply to CaCO3? A. metal + polyatomic anion B. polyatomic cation + nonmetal anion(ide)
Sveta_85 [38]
The naming rules for CaCO3 would be A. Metal+ Polyatomic Anion.
7 0
3 years ago
Read 2 more answers
Classify each of the following changes as Physical or Chemical:
ddd [48]

Explanation:

Physical changes are the changes that does not lead to any change in chemical composition of a substance.

For example, mass, density, volume are all physical changes.

On the other hand, a change that leads to formation of a new compound by changing the chemical composition of reactants or combining atoms is known as a chemical change.

For example, combustion, toxicity, reactivity etc are all chemical changes.

Therefore, given changes are identified as follows.

  • Coal burning : It is a combustion reaction. Hence, it is a chemical change.
  • Ice melting : Physical state of water changes from solid to liquid. Hence, it is a physical change.
  • mixing chocolate syrup with milk : No new compound is forming as there is no chemical reaction occurring. Hence, it is also a physical change.
  • explosion of a firecracker : It shows reactivity of fire cracker. Hence, it is a chemical reaction.
  • magnetizing of a screwdriver : It shows physical attraction between the magnet and screwdriver. Hence, it is a physical change.

6 0
3 years ago
A solution is prepared by dissolving 0.5636 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliq
zepelin [54]

Answer:

The final molarity of the diluted oxalic acid solution is 0.002504 M

Explanation:

Step 1: Data given

Mass of oxalic acid (H2C2O4) = 0.5636 grams

Volume of the solution = 100.0 mL = 0.100 L

A 10 ml of this solution diluted in 250 ml of solution.

Molecular weight of H2C2O4  = 90.03 g/mol

Step 2: Calculate  initial moles of H2C2O4

Moles H2C2O4  = mass / molar mass

Moles H2C2O4  = 0.5636 grams / 90.03 g/mol

Moles H2C2O4 = 0.00626 moles

Step 3: Calculate molarity of the solution

Molarity = moles / volume

Molarity = 0.00626 moles / 0.100 L

Molarity = 0.0626 M

Step 4: Calculate moles of a 10.00 mL aliquot

Moles = 0.0626 M * 0.010 L

Moles = 0.000626 moles

Step 5: Calculate the new molarity

Molarity = 0.000626 moles / 0.250 L

Molarity = 0.002504 M

The final molarity of the diluted oxalic acid solution is 0.002504 M

6 0
3 years ago
A 20. 0-liter flask contains a mixture of argon at 0. 72 atmosphere and oxygen at 1. 65 atmospheres. What is the total pressure
exis [7]

The total pressure of the system is equivalent to the sum of all the pressure of the individual gases. The total pressure of the flask is 2.37 atm.

<h3>What is total pressure?</h3>

According to Dalton's law, the total pressure of the system will be equivalent to the total of the pressures exerted by the individual gases present in the system.

The total pressure of gases is given as,

\rm P = P_{1} +P_{2}+ P_{3}.....P_{n}

Given,

  • The pressure of argon gas = 0.72 atm
  • The pressure of oxygen = 1.65 atm
  • Total pressure = P

Substituting values in the above equation:

\begin{aligned}\rm P &= 0.72 + 1.65\\\\&=2.37\;\rm atm\end{aligned}

Therefore, 2.37 atm is the total pressure of the flask.

Learn more about total pressure here:

brainly.com/question/11150092

5 0
3 years ago
You need a 70% alcohol solution. On hand, you have a 135 mL of a 20% alcohol mixture. You also have 85% alcohol mixture. How muc
frutty [35]

To obtain the desired solution:

450 mL of 85% alcohol solution is needed to obtain the desired solution.  

Calculation:

Let x be the amount of the 85% alcohol required

The volume of the resulting 70% alcohol solution will then be = x + 135 ml

135 mL of the 20% alcohol solution contains the amount of "pure" alcohol is =  0.20×135 mL.

The 85% alcohol solution contains x mL of "pure" alcohol = 0.85× x mL.

The total amount of the "pure" alcohol is the sum

=  0.20×135 + 0.85× x mL.

It should be equal to the amount of the "pure" alcohol in the mixture, which is = 0.70× (x+135) ml.

So, your "pure alcohol" equation is,  

=  0.85× x + 0.20×135 = 0.70× (x+135)

Simplify and solve it for x:

0.85x + 0.20×135 = 0.70x + 0.70×135,

0.85x - 0.70x = 0.70×135 - 0.20×135,

0.15x = 67.5

x = 67.5/0.15

= 450mL.

Learn more about the alcohol solution here,

brainly.com/question/12246176

#SPJ4

 

7 0
2 years ago
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