Mitochondrion (mitochondria)
given days = 42 days
So, number of half life, n = 42/14.3 = 2.93
So, after 42 days, the mass of sodium phosphate sample left = original mass
x (1/2)^n,
= 157 mg x (1/2)^2.93 = 20.60 g of Na3PO4 after 42 days
Formula mass of Sodium phosphate = 3(23) + 32 + 4(16) amu = 165 amu
165 g of sodium phosphate contains 32 g of Phosphorus
20.60 g ------------------------------? = 20.60 x 32/ 165 =3.99g of P32
The answe is 56 setup the word primooo
the volume of 2.5% m/v koh which can prepared from 125 ml of a 5% koh solution is calculated using the following formula
m1v1= m2 v2
M1= 5/100= 0.05
v1= 125
m2=2.5/100=0.025
V2=?
v2= m1v1/m2
=0.05 x125 /0.025=250 ml
