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KatRina [158]
3 years ago
5

Why doesn’t a stable ecosystem have more tertiary consumers than primary consumers?

Chemistry
1 answer:
ruslelena [56]3 years ago
5 0
Tertiary consumers are usually big predators which 
1) have a tendency to claim large territories for themselves 
2) need more energy and thus eat more than primary consumers 
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what are the limitations of litmus paper and phenolphthalein indicatiors? Name two other indicators that can be used that do not
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Limitations of litmus paper and phenolphthalein:

They do not give the numerical pH value.

Can differentiate only between a very strong acid and base.

The colour change can be for reasons other than acid- base reactions.

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The litmus test is quick and simple, but it suffers from a few limitations. First, it's not an accurate indicator of pH; it does not yield a numerical pH value. Instead, it roughly indicates whether a sample is an acid or a base. Second, the paper can change colors for other reasons besides an acid-base reaction.

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give the spectator ions for the reactions that occur when aqueous solutions of H2SO4 and KOH are mixed. Thank you so much.
zvonat [6]

Potassium ions and sulfate ions.

<h3>Explanation</h3>

Start with the chemical equation for this reaction.

Sulfuric acid \text{H}_2\text{SO}_4 is a strong acid. Potassium hydroxide \text{KOH} is a strong base. Acids neutralize base in aqueous environments to produce a salt and water.

That is:

Sulfuric Acid + Potassium Hydroxide → Potassium sulfate + Water

\text{H}_2\text{SO}_4 \; (aq) + 2\; \text{KOH} \; (aq) \to \text{K}_2\text{SO}_4 \; (aq) + \text{H}_2\text{O} \; (l)

Rewrite the chemical equation as an ionic one. Take all strong electrolytes- including strong acids, strong bases, and soluble salts- apart as their comprising ions. Do not take water molecules apart. As a weak electrolyte, water molecules barely disassociate to produce ions.

2 \; \text{H}^{+} \; (aq) + \text{SO}_4^{2-} \; (aq) + 2 \; \text{K}^{+} \; (aq) + 2 \; \text{OH} \; (aq)\\ \to 2\; \text{K} \; (aq) + \text{SO}_4^{2-} \; (aq) + 2\; \text{H}_2 \text{O} \; (l)

Ions that are present on both sides of the equation by the same quantity do not take part in the net reaction. They are thus considered spectator ions.

  • Potassium ions \text{K}^{+}
  • Sulfate ions \text{SO}_4^{2-}
5 0
3 years ago
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