Question

How many liters of 30% salt solution must be added to 6 L of an 80% salt solution to obtain a 50% salt solution

Answer 1

Answer:

9 Liters

Step-by-step explanation:

Let us represent:

The number of liters of the 30% salt solution = x

Number of liters for the 80% solution = 6 Liters

Number of liters for the 50% solution = x + 6 Liters

Hence:

x × 30% + 6 × 80% = (x + 6)50%

0.3x + 4.8 = 0.5x + 3

Collect like terms

4.8 - 3 = 0.5x - 0.3x

1.8 = 0.2x

x = 1.8/0.2

x = 9 Liters

Therefore, the number of liters for the 30% Salt solution = 9 Liters