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DaniilM [7]
2 years ago
11

(true or false).. the absolute value of a real negative number is negative.

Mathematics
1 answer:
nadezda [96]2 years ago
5 0

Answer:

False

Step-by-step explanation:

The absolute value shows the distance a value is from 0, which is always positive.

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Here are scores for two softball teams for seven innings. Each team's total score is the sum of the numbers in its row. Rosie's
gladu [14]

Answer:

<h2> T<u>he Susans Bees lost by </u><u>3</u><u> points.</u></h2>

Step-by-step explanation:

Rosie's Riveters has 13 points in all.

The Susans Bees have 10 points in all.

13 - 10 = 3.

5 0
2 years ago
What does y=1\4X-5 equal
Tema [17]

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y= -5/4

Step-by-step explanation:

download a app called math papa. it's a great cheat cheat for these types of problems

8 0
3 years ago
You have 60 CD cases that you would like to store on a shelf that is 24 inches long. if each CD case is 3/8 inch wide, is there
Jet001 [13]
Yes you do.

The shelf is 24 in. long, so to fit, the total width of all the cases must be < 24 in.

If each case is 3/8 inches:
60 * 3/8 = 22.5

22.5 < 24, therefore they will all fit.
5 0
3 years ago
Read 2 more answers
What is 3/2 in a mixed number
antoniya [11.8K]
Bonjour ,
 
3/2 = 2/2 + 1/2 
3/2 =    1  + 1/2
3/2 = 1  \frac{1}{2}
7 0
2 years ago
Read 2 more answers
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
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