The fraction of a defective item getting by both inspectors is
= 
Step-by-step explanation:
Step 1; Assume that the probability of the first inspector missing a defective part is P(A) and the probability of the second inspector missing those that do get past the first inspector is P(B).
Step 2; It is given that P(A) = 0.1, we convert this into a fraction so that the final probability will be a fraction and not a decimal.
P(A) = 0.1 =
.
It is given that the second inspector misses 5 out of 10 that get past the first inspector, so P(B) =
.
Step 3; To calculate the probability of both inspectors missing a defective part, we multiply both the probabilities.
P(A and B happening) = P(A) × P(B) =
×
=
=
= 0.05%. So there is a 0.05% chance of both inspectors missing a defective part.
Part A:<span> What is the mean of the data? Show your work. (4 points)</span>
Part B:<span> Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)
</span>
To move a graph up c units, add c to the whole function
so basicaly what you did is you subtraced 3 from the whole function
the whole graph shifts 3 units down
B is answer