Fermat's little theorem states that

≡a mod p
If we divide both sides by a, then

≡1 mod p
=>

≡1 mod 17

≡1 mod 17
Rewrite

mod 17 as

mod 17
and apply Fermat's little theorem

mod 17
=>

mod 17
So we conclude that

≡1 mod 17
You would set up a proportion. 3/8 = 6/x... cross multiply ( 3*x = 3x and 6*8 = 48) 3x = 48... divide both sides by 3 (3x/3 = x and 48/3 = 16)
So, she originally had 16 feet of ribbon.
Add up the x points and divided by 2
same to go for the y points
so the and is (4,-2)
So you convert the fraction into a decimal then multiply it by 100 so the percentage would be 180%
Equation a^2 + b^2 = c^2
c = longest side, unknown
The answer is D.
12^2 + 10^2 = c^2