Answer:
is this science?
Step-by-step explanation:
Answer:
Step-by-step explanation:
let the consecutive even numbers be 2n-2,2n,2n+2,2n+4 where n>0 and n is an integer.
2n(2n+2)-(2n-2)(2n+4)
=4n²+4n-(4n²+8n-4n-8)
=4n²+4n-4n²-8n+4n+8
=8
Step-by-step explanation:
According to the question a(n) = -5 for all real values of n.
So the 12th term in the sequence is -5.
Answer: If 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.
Step-by-step explanation:
- We know that when a complex number
is a root of a polynomial with degree 'n' , then the conjugate of the complex number (
) is also a root of the same polynomial.
Given: 7+5i is a zero of a polynomial function of degree 5 with coefficients
Here, 7+5i is a complex number.
So, it conjugate (
) is also a zero of a polynomial function.
Hence, if 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.