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Mrac [35]
3 years ago
6

Nora's math teacher said that each question answered correctly on a test would be

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

add one please i wanna help!

Step-by-step explanation:

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URGENT 8th grade math
goldenfox [79]

Answer:

inequality is n< with the line under 12 or n= , with the line under it 12

Step-by-step explanation:

4 0
3 years ago
URGENT PLEASE HELP 50 POINTS AND WILL NAME BRAINLIEST An ice cream store has the pricing shown below. You want to determine the
kow [346]

u take x then multiply it by b, the add 9 to x then we will get the answer xb9x, hope u understand;>

5 0
2 years ago
Can anyone help please
Akimi4 [234]

Answer: X = 27

Step-by-step explanation: If we observe very closely, we have two similar triangles in the diagram. The first one is ABC and the other triangle is EDC. Also take note that angle ACB in the first triangle is equal in measurement to angle ECD (45 degrees) in the other triangle, (Opposite angles).

Hence in triangle ECD, we have identified two angles so far which are angle 2x + 10 and angle 45. Same applies to triangle ABC, we already have two angles which are, 3x - 10 and 45.

However angle D in the second triangle is equal in measurement to angle B in the first triangle

(Alternate angles).

Hence we have a third angle in triangle ABC which is

Angle B = 2x + 10.

Therefore 3x - 10 + (2x + 10) + 45 = 180

(Sum of angles in a triangle)

3x - 10 + 2x + 10 + 45 = 180

By collecting like terms we now have

3x + 2x = 180 + 10 - 10 - 45

5x = 135

Divide both sides by 5,

x = 27

8 0
3 years ago
Multiply 3xyz ^ 2 / 6y ^ 4 by 2y / x z ^ 4
Marat540 [252]

\dfrac{3xyz^2}{6y^4}=\dfrac{3}{6}\cdot\dfrac{xyz^2}{y^4}=\dfrac{1}{2}\cdot\dfrac{xz}{y^3}=\dfrac{xz}{2y^3}\\\\\\\dfrac{3xyz^2}{6y^4}\cdot\dfrac{2y}{xz^4}=\dfrac{xz^2}{2y^3}\cdot\dfrac{2y}{xz^4}=\dfrac{2}{2}\cdot\dfrac{xyz^2}{xy^3z^4}=1\cdot\dfrac{1}{y^2z^2}=\dfrac{1}{y^2z^2}

8 0
3 years ago
Read 2 more answers
Solve x^2 – 8x + 41 = 0 for x.
icang [17]
<span>\displaystyle x^2 - 8x + 41 = 0 \\\\ \Delta=b^2-4ac \\ \Delta=(-8)^2-4\cdot1\cdot41 \\ \Delta=64-164 \\ \Delta=-100 \\ \\ X_{1,2}= \frac{-b\pm i \sqrt{-\Delta} }{2a} = \frac{8 \pm 10i}{2} \\ \\ X1=4-5i \\ \\ X2=4+5i</span>
5 0
3 years ago
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