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morpeh [17]
3 years ago
10

(look at image) can i get help with this?

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

Answer:

m∡A = 14

m∡B = 76

Step-by-step explanation:

Two Angles are Complementary when they add up to 90 degrees.

So 3x -7 + 11x - 1 = 90, which we can solve.

14x - 8 = 90

14x = 98

x = 98/14 = 7

with the knowledge of x=7, we can find the angles:

m∡A = 3·7 - 7 = 14

m∡B = 11·7 - 1 = 76

Supplementary angles are angles that add up to 180 degrees, so the next assignment is very comparable, try it!

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What value of x is in the solution set of 8x – 6 &gt; 12 + 2x?<br> –1<br> 0<br> 3<br> 5
Alika [10]

Isolate the x.

8x - 6 > 12 + 2x

Add 6 to both sides, and subtract 2x from both sides

8x (-2x) - 6 (+6) > 12 (+6) + 2x (-2x)

8x - 2x > 12 + 6

Simplify. Combine like terms

8x - 2x > 12 + 6

6x > 18

Isolate the x. Divide 6 from both sides

6x/6 > 18/6

x > 18/6

x > 3

Any number that is greater than 3 (3 not included), is your answer.

5 is your answer

hope this helps

4 0
4 years ago
Read 2 more answers
Need help on this asap
Studentka2010 [4]

The dotted line represents y = x


area below this is y < x


Also y < 4 ( below the horizontal dotted line


Its choice C.

3 0
3 years ago
Read 2 more answers
Help, please! I appreciate you taking the time to help me<br> question attached
nirvana33 [79]
F(gx)
f(-x-4) = 2(-x-4) + 3
F(-x-4)= -2x-8+3
F(-x-4)= -2x-5

G(fx)
G(2x+3)= -(2x+3) -4
G(2x+3)= -2x-3-4
G(2x+3)= -2x-7

F(hx)
F(x^2)=2x^2+3

H(fx)
H(2x+3)= (2x+3)^2
H(2x+3)= (2x^2) + 2(2x)(3)+3^2
H(2x+3)= 4x^2+12x+9

[I think I messed up with the last one. I didn’t know how to get the correct answer for that. Sorry ]
3 0
3 years ago
Write an equation for a sine curve that has the given amplitude and period, and which passes through the given point.
Delicious77 [7]

ANSWER

y = 5\sin( \frac{\pi}{3} x  -  \frac{2\pi}{3} )

EXPLANATION

Let the equation of the sine curve be of the form;

y = a \sin(bx + c)

where a=5 is the amplitude and period,

\frac{2\pi}{b}  = 6

This implies that

b =  \frac{2\pi}{6}

b =  \frac{\pi}{3}

We substitute the values we got so far into our equation to obtain;

y = 5\sin( \frac{\pi}{3} x + c)

When we substitute (2,0) we obtain;

0= 5\sin( \frac{2\pi}{3}  + c)

Solve for c.

\sin( \frac{2\pi}{3}  + c)  = 0

\frac{2\pi}{3}  + c =   \sin^{ - 1} (0)

\frac{2\pi}{3}  + c =   0

c =  - \frac{2\pi}{3}

Hence our equation becomes

y = 5\sin( \frac{\pi}{3} x  -  \frac{2\pi}{3} )

The correct choice is D.

4 0
3 years ago
Hey! I hope you’ve had a good day:) I just need help in geometry right now. Can someone take a look at this question?
KonstantinChe [14]

Answer:

(5,2)

Step-by-step explanation:

midpoint formula for future reference

(x1+x2/2),(y1+y2/2)

(3+7/2),(-5+9/2)

(10/2),(4/2)

(5,2)

6 0
3 years ago
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