Answer:

Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=b^{2}+4[\frac{1}{2}bh]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7Dbh%5D)
where
b is the length side of the square base
h is the height of the triangular face
Remember that
Each lateral triangular face is a triangle 45°-90°-45°
so

we have

so

substitute in the formula
![SA=6^{2}+4[\frac{1}{2}(6)(3)]=72\ ft^{2}](https://tex.z-dn.net/?f=SA%3D6%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%286%29%283%29%5D%3D72%5C%20ft%5E%7B2%7D)
Answer:
A=72CM^2
Step-by-step explanation:
The answer is 72cm^2 because the area of a triangle is h x b divided by two because the triangle is half of a square, since the square is side times side, the answer is 12x12 divided by two, wich is 144/2. The final answer is 72
Slope (y2-y1)/(x2-x1)
(0-4)/(-5-5) = -4/-10 = 2/5
Y = 2/5x + b
Plug in any point
4 = 2/5(5) + b
4 = 2 + b, b= 2
Final equation: y = 2/5x + 2
Answer:
Graph the line using the slope and y-intercept, or two points.
Slope: −1
y-intercept: (0,0)
x y
0 1
0 −1
Step-by-step explanation: