Answer:
The correct order of the steps is CEABD ⇒ B
Step-by-step explanation:
Let us arrange the figures
To construct a bisector of an angle
First: Draw angle AOB
First step is figure C
Second: Place the pin of the compass on point O and draw an arc intersects the two sides of the angle OA and OB at points D and E
Second step is figure E
Third: Place the compass on point D and draw an arc in the interior of the angle
Third step is figure A
Fourth: without change the open of the compass place its pin on point E and draw an arc which intersects the arc drawn from point D at point C
Fourth step is figure B
Fifth: Draw a line from point A to point C, this line AC is the bisector of angle AOB
Fifth step is figure D
The correct order of the steps is CEABD
9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
You solve for the domain by setting the radicand less than or equal to 0 and solving for x. Dividing by a -x, we switch the sign so we have that the domain is less than or equal to 0, or all negative numbers. We know that it breaks every law in math to have a negative radicand with an even index, so if the domain is all negative values of x, taking a negative of a negative gives us a positive. The negative sign OUTSIDE the radical means you are flipping the graph upside down. So instead of having a range of y is greater than or equal to 0 as does the parent graph, you have flipped it upside down so it heads more negative in regards to the range. Therefore, the domain and the range both have the same sign, thee last choice from above.
(m - n)(r - s) Hope this helps and heve a nice day!
