Answer:
why are you asking me ask jose
Answer: 
Remember: RISE/RUN (y/x). Lines that are increasing have a positive slope, and lines that are decreasing have a negative slope.
You can find the slope in two ways:
1. Useful if the line is graphed: count the units between 2 points on the line.
- Let's use the points (-1, 4) and (4, -4).
- (-1, 4) is 8 units higher than (4, -4) and 5 units to the left of (4, -4).
- Because the line is decreasing, the slope is negative.
- Therefore, the slope is
.
2. Useful if the line is not graphed: find the difference between the y-coordinate values divided by the difference of the x-coordinate values.
- Let's use the points (-1, 4) and (4, -4).

- Therefore, the slope is
.
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
2.8 units
Step-by-step explanation:
Think of this distance as the hypotenuse of a right triangle that has a vertical leg and a horizontal one as well.
Going from P to Q, the change in x is 2 and the change in y is also 2.
Thus, by the Pythagorean Theorem, this desired distance is:
d = √(2^2 + 2^2) = 2√2 units, or 2.8 units