Question

How many grams of carbon dioxide are produced when 255 grams of octane (C3H18) combust?

Answer 1

Answer:

787.3 g of CO₂

Explanation:

The combustion of octane is this one:

2C₈H₁₈  +  25O₂  →   16CO₂  +  18H₂O

2 moles of octane react to 25 moles of oxygen in order to produce 16 moles of CO₂ and 18 moles of water.

The products in combustion reactions are always CO₂ and H₂O. The oxygen is always a reactant.

We convert mass to moles: 255 g . 1mol /114g = 2.24 moles

2 moles of C₈H₁₈ can produce 16 moles of CO₂

Then, 2.24 moles may produce (2.24 . 16)/2 = 17.9 moles of CO₂

We convert moles to mass:

17.9 mol . 44g/mol = 787.3 g of CO₂