Hey there !
Yeah , the problem is absolutely correct , and here is the solution -
To find inverse , first switch x and y ,
Taking log both sides ,
Hope it helps you :)
Answer:
The fraction of females on the maths course at university is 3/4
Step-by-step explanation:
Males = x
Females = 3x
Males + Females = x + 3x = 4x
The fraction of the course that are females
Females fraction = Females/Males + Females
Females fraction = 3x/4x= 3/4
which means that for every 4 people 3 are females and 1 male
Answer:
log5 (4/7)= log5 (4)- log5 (7)=-0.347708839
Step-by-step explanation:
for the first question which would be Approximate: log5 4/7 the answer would be B. –0.3477
and for the second question which would be Approximate: log1/2 5 the answer would be C.–2.3219
It is 80.2 when rounded to the nearest 10th
Answer: x = 4
y = - 3
Step-by-step explanation:
The given system of simultaneous equations is expressed as
x-3y = 13 ------------------------1
2x+4y=-4--------------------------2
We would apply the method of substitution in solving the equations. From equation 1, we would make x to stand alone by adding 3y to the left hand side and the right hand side of the equation. It becomes
x - 3y + 3y = 13 + 3y
x = 13 + 3y
Substituting x = 13 + 3y into equation 2, it becomes
2(13 + 3y) + 4y = - 4
26 + 6y + 4y = - 4
26 + 10y = - 4
Subtracting 26 from the left hand side and the right hand side of the equation, it becomes
26 - 26 + 10y = - 4 - 26
10y = - 30
Dividing the left hand side and the right hand side of the equation by 10, it becomes
10y/10 = - 30/10
y = - 3
Substituting y = - 3 into x = 13 + 3y, it becomes
x = 13 + 3 × - 3
x = 13 - 9
x = 4