20.06 g of Hg and 1.6 g of O₂
<u>Explanation:</u>
To Find:
Number of Mercury and oxygen that can be obtained from 21.7 g of HgO
First we have to write the balanced equation for the decomposition reaction of Mercury(II) oxide as,
2 HgO (s) → 2Hg(l) + O₂ (g)
21.7 g of HgO = 
= 0.1 mol of HgO.
As per the above equation, we can find the mole ratio between HgO and Hg is 1: 1 and that of HgO and oxygen is 2:1 .
So amount of Hg produced = 0.1 mol × 200.59 g / mol ( molar mass of Hg)
= 20.06 g of Hg
Amount of oxygen produced = 0.05 mol × 32 g/ mol = 1.6 g of O₂
Thus it is clear that 20.06 g of Hg and 1.6 g of O₂ is obtained from 21.7 g of HgO
The answer is D hope this helps
Answer:
Order of the cycle:
Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.
Explanation:
<u>Step -1:</u>
Carbon dioxide is taken in by plants during photosynthesis.
<u>Step -4;</u>
The animal eats a plant and uses its carbohydrates for energy.
<u>Step - 3</u>
The animal releases the carbon dioxide back into the atmosphere during respiration.
<u>Step -2</u>
The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is taken in.
Therefore, order of the cycle is Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.
Answer:
H₂(g) + Cl₂(g) → 2HCl(g) + 185kJ
Explanation:
In a chemical reaction, enthalpy of reaction ΔH is a thermodynamic constant that gives information if the reaction is exothermic (Produce heat if reacts) or endothermic (Consume heat if reacts).
In the reaction:
H₂(g) + Cl₂(g) → 2HCl(g) ΔH = -185kJ
As ΔH <0, the reaction is exothermic, that means, <em>produce heat</em>, writing a balanced thermochemical equation:
<em>H₂(g) + Cl₂(g) → 2HCl(g) + 185kJ</em>
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The enthalpy is as a product beacause an exothermic reaction produces heat.
I hope it helps!
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Hey there!
D = m / V
13.6 = 76.2 / V
V = 76.2 / 13.6
V = 5.602 mL
