Answer:
Explanation:
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In this case, since the combustion of B2H6 is:
Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:
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The allowable combination for the atomic orbital is n=3, l=1 or 2, =+1.
Three quantum numbers specify an atomic orbital:
- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.
- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),
- is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus;
values are integers from -l to =l(l limits ml)
For n = 3, l can have three values: 0, 1, and 2. Hence, the l value must be lower than 3. Because of = +1, the l value must be higher than 0. Two l values are consistent with n and
values:
l= 1 or 2
Therefore, the allowable condition is n=7, l=1 or 2, =+3.
To know more about quantum numbers, visit: brainly.com/question/16979660
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