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aliina [53]
2 years ago
9

What physical and chemical properties should braces (used to straighten teeth possess in order to attain its desired goal to str

aighten the teeth) while not presenting a health hazard to the individual?
Chemistry
1 answer:
Nitella [24]2 years ago
6 0

Answer: Braces are used by the people to correct the alignment and position of tooth or teeth in the jaw.

Explanation:

The teeth braces must have strong tensile strength and must create a constant pressure on the teeth so as to allow the straightening of the teeth.

The strong force of attraction between the molecules of the braces material that can be steel, nickel, molybdenum, copper, titanium. This makes the bracing material rigid on the teeth.

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Energía necesaria para arrancar un electrón de un átomo neutro​
zalisa [80]
La energía de ionización o potencial de ionización, es la energía necesaria para extraer un electrón de un átomo neutro. Por ejemplo, cuando un átomo de cloro neutro en forma gaseosa recoge un electrón para formar un ion Cl-, libera una energía de 349 kJ/mol o 3,6 eV/átomo.

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5 0
3 years ago
At 25∘C, the decomposition of dinitrogen pentoxide, N2O5(g), into NO2(g) and O2(g) follows first-order kinetics with k=3.4×10−5
Annette [7]

Answer:

4600s

Explanation:

2N_{2}O_{5}(g) - - -> 4NO_{2}(g) +O_{2}

For a first order reaction the rate of reaction just depends on the concentration of one specie [B] and it’s expressed as:

-\frac{d[B]}{dt}=k[B] - - -  -\frac{d[B]}{[B]}=k*dt

If we have an ideal gas in an isothermal (T=constant) and isocoric (v=constant) process.

PV=nRT we can say that P = n so we can express the reaction order as a function of the Partial pressure of one component.  

-\frac{d[P(B)]}{P(B)}=k*dt  

-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=k*dt

Integrating we get:

\int\limits^p \,-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=\int\limits^ t k*dt

-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])=k(t_{2}-t_{1})

Clearing for t2:

\frac{-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])}{k}+t_{1}=t_{2}

ln[P(N_{2}O_{5})]=ln(650)=6.4769

ln[P(N_{2}O_{5})_{o}]=ln(760)=6.6333

t_{2}=\frac{-(6.4769-6.6333)}{3.4*10^{-5}}+0= 4598.414s

4 0
3 years ago
Atmospheric pressure yesterday was given as 0.875 atm. Express this pressure in units of torr and also in kilopascals (kPa), res
Aneli [31]
This problem is about conversion and dimensional analysis. Important information to know:
 1 atm = 760 torr = 101.325 kPa

For atm to torr conversion:

0.875 atm * (760 torr / 1 atm) = 665 torr

For atm to kPa conversion:

0.875 atm * (101.325 kPa / atm) = 88.7 kPa

Thus the answer is b) 665 torr and 88.7 kPa
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3 years ago
HELP LAST QUESTION WILL MAKE BRAINLIEST
Alenkasestr [34]

Answer:

I think it is C.)????

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Changes between a liquid and gas exsample​
exis [7]

Here are some examples:-

Water → water vapour

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