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lesantik [10]
3 years ago
9

Please help! Solve: 2/3 + x = 3

Mathematics
1 answer:
Vlad [161]3 years ago
3 0
The answer is 7/3

2/3+x=3

x=3-2/3

X= 7/3

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A full bag of dog food weighs 5 1/2 pounds.
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In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph
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Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

f(x)=(x-2)^{2}+1

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The function g(x) is given by:

g(x)=f(x-1)

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2(x-3)=0

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Puting it on g(x) we will get y value.

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y=g(3)=1

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

g(x)=f(x+2)

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Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2x

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Evaluatinf g(x) at this value of x we have:

g(0)=(x)^{2}+1

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<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

g(x)=f(x)+2

g(x)=(x-2)^{2}+1+2

g(x)=(x-2)^{2}+3

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}+3

g(2)=3

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

g(x)=f(x)-3

g(x)=(x-2)^{2}+1-3

g(x)=(x-2)^{2}-2

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}-2

g(2)=-2

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

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Answer:

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Answer:

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This is what youll get when u multiply

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