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d1i1m1o1n [39]
2 years ago
5

Please help me solve this HCF​

Mathematics
2 answers:
notsponge [240]2 years ago
8 0

Answer:

<u>(x + y)</u>

Step-by-step explanation:

<u>Factorizing both terms</u> :

  • x² - y² = (x + y)(x - y)
  • (x + y)² = (x + y)(x + y)

The HCF of the terms is (x + y).

Rina8888 [55]2 years ago
5 0

Answer:

(x+y)

Step-by-step explanation:

{x}^{2}   -  {y}^{2}  = (x + y)(x - y)

Thus, the HCF is (x+y).

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4 0
4 years ago
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8 0
3 years ago
Find the zero of the function by rewriting the function in intercept form
Marat540 [252]
Given a quadratic function
y = 4x² - 19x - 5
or i will write it as
4x² - 19x - 5 = y

Zero of the function is when y have the value of zero.
So the quadratic equation will be
4x² - 19x - 5 = y
4x² - 19x - 5 = 0

Now make the equation to intercept form by factorization
4x² - 19x - 5 = 0
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Solution 1
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Solution 2
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SUMMARY
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