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WARRIOR [948]
3 years ago
5

Does 6/4 = 1 2/4? I need awnsers by tmrw

Mathematics
1 answer:
Gala2k [10]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

There is definetly a whole number so thats correct

1. subtract 4 from 6 equals 2

2. turn that 4 to a 1 whole and leave what's alone

3. Look at what you did... 1 2/4

4. Take pride

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There are 28 students in a class. the teacher separates them into 7 equal groups. which equation can be used to find s, the numb
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S = total # of students / #of students in each group
So you can do, s= t/g
Overall, the answer is 4 students per group
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The ratio of boys to girls in a class is 3:4. There are 35 students in the class. How many students are girls?
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There would be 20 girls
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Find the slope if it exists, of the line containing the pair (3,4) and (3,-7)
borishaifa [10]
So you've got a cartesian plane, right? There are two coordinates here. Plot the first one ((3.4)) first. the '3' is on the x axis and the '4' is on the y axis. Go 3 across until you get to 3. and then go 4 up. Put a dot there.
Next, also plot the second one. To do this, go to 3 on the x axis, and then go down until you get to -7 on the y axis. Plot your point with a dot. Then, join the dots up, and hopefully, it'll be a linear relationship! 
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3 years ago
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You have a choice of receiving a wage of $26,000 per year, $2860 per month, $630 per week, or $14.30 per hour. Which pay choice
matrenka [14]

Answer:

I think the answers is B

Step-by-step explanation:

But im so sorry if its not right...

<em>H</em><em>a</em><em>v</em><em>e</em><em> </em><em>a</em><em> </em><em>n</em><em>i</em><em>c</em><em>e</em><em> </em><em>d</em><em>a</em><em>y</em>

4 0
3 years ago
Consider a collection of envelopes consisting of 1 red envelope, 3 blue envelopes, 2 green envelopes, and 3 yellow envelopes if
nasty-shy [4]

Answer:

the probability that at least one envelope is a yellow envelope is 16/21

Step-by-step explanation:

The probability that at least one envelope is a yellow envelope is P(Y);

P(Y) = 1 - P(Y)'

P(Y)' is the probability that no envelope is a yellow envelope.

Given;

red envelope = 1

blue envelopes = 3

green envelopes = 2

yellow envelopes = 3

Total = 9

Number of non-yellow envelope = 9 -3 = 6

(6 envelope are not yellow)

P(Y)' = P1 × P2 × P3

Since there is no replacement;

P(Y)' = 6/9 × 5/8 × 4/7

P(Y)' = 5/21

From equation 1;

P(Y) = 1 - 5/21

P(Y) = 16/21

the probability that at least one envelope is a yellow envelope is 16/21.

8 0
3 years ago
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