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Phoenix [80]
2 years ago
15

Solve for x! please help (show work)

Mathematics
2 answers:
guapka [62]2 years ago
6 0

Answer:

x=4

Step-by-step explanation:

Solving for x, we get:

16=2(3x-6)+x

16=2*3x+2(-6)+x (Distributive Property of Multiplication)

16=6x-12+x (Multiply distributed terms)

16=7x-12 (Combine like terms)

16+12=7x-12+12 (Add 12 to both sides of the equation to isolate x)

28=7x (Combine like terms / Simplify)

\frac{28}{7}=\frac{7x}{7} (Divide both sides of the equation by 7 to get rid of x's coefficient)

\bf x=4 (Simplify / Symmetric Property of Equality)

Hope this helps!

suter [353]2 years ago
5 0

Step-by-step explanation:

16 = 2(3x - 6) + x \\ 16 = 6x - 12 + x \\  - 6x  - x =  - 12 - 16 \\  - 7x =  - 12 - 16 \\ 7x = 12 + 16 \\ 7x = 28 \\ x =  \frac{28}{7}  \\ x = 4

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Please help me !!!!!!!!!!!!!!!!
Nutka1998 [239]

Answer: x=-10, y=13

Step-by-step explanation:

-3x+2y=56\\-5x-2y=24

+2y-2y = 0, eliminating y is much easier. So -3x-5x = -8x and 56+24 = 80

-8x=80\\x=-10

Substitute x in any equations but only 1 equation (Don't substitute in both equations.)

For me, I'd substitute x in -3x+2y=50

-3(-10)+2y=56\\30+2y=56\\2y=56-30\\2y=26\\y=13

So the answer is x = -10, y = 13

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3 years ago
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3 years ago
The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 4, m2 = 3, m3
viva [34]

Answer:

M_x= 8

M_y = 6

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

Step-by-step explanation:

Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.

Center of mass of a triangle is the centriod of a triangle.

Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)

M_x = ∑(mass × x-co-ordinate)

M_y = ∑(mass × y-co-ordinate)

Therefore  

M_x = (4×2)+{3×(-3)}+(3×3)

     =8

M_y = {4×(-3)}+{3×1}+(3×5)

    =6

The x co-ordinate of the center of mass is the ratio of M_x to the total mass.

The y co-ordinate of the center of mass is the ratio of M_y to the total mass.

Total mass (m) = m₁+ m₂+ m₃

                        = 4+3+3

                        =10

The x co-ordinate of the center of mass is \frac {8}{10} = \frac {4}{5}

The y co-ordinate of the center of mass is \frac{6}{10}=\frac{3}{5}

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

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3 years ago
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