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Hunter-Best [27]
3 years ago
5

-5 (x-1)-x+1 = -18 help please​

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0

Answer:

The value of x is 4.

Step-by-step explanation:

-5(x-1)-x+1= -18

or, -5x+5-x+1=-18

or, -6x+6= -18

or, -6(x-1)=-18

or, x-1=3

or, x=4

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PLEASE HELP ASAP
maria [59]

Answer:

First option:  3x^2-5x=-8

Second option: 2x^2=6x-5

Fourth option: -x^2-10x=34

Step-by-step explanation:

Rewrite each equation in the form ax^2+bx+c=0 and then use the Discriminant formula for each equation. This is:

D=b^2-4ac

1) For 3x^2-5x=-8:

 3x^2-5x+8=0

Then:

D=(-5)^2-4(3)(8)=-71

Since D this equation has no real solutions, but has two complex solutions.

2) For 2x^2=6x-5:

 2x^2-6x+5=0

Then:

D=(-6)^2-4(2)(5)=-4

Since D this equation has no real solutions, but has two complex solutions.

3) For 12x=9x^2+4:

 9x^2-12x+4=0

Then:

D=(-12)^2-4(9)(4)=0

Since D=0 this equation has one real solution.

4) For -x^2-10x=34:

 -x^2-10x-34=0

Then:

D=(-10)^2-4(-1)(-34)=-36

Since D, this equation has no real solutions, but has two complex solutions.

3 0
3 years ago
A jacket at Academy is $60. You have a coupon for 20% off. What is the new price?
svetlana [45]

Answer:

$48

Step-by-step explanation:

7 0
3 years ago
Find the exact solution of x.
MA_775_DIABLO [31]

Answer:

the answer is a . hope this helps

4 0
3 years ago
Read 2 more answers
A rectangle has a perimeter of 30m. The length is 10m. Solve the following equation to find the width: 2w+ 2(10)= 30
NARA [144]

2w+2(10)=30

multioly the 2 and 10

2w+20=30

subtract 20

2w=10

divide by 2

w=5

plz rate as brainliest answer


5 0
3 years ago
Read 2 more answers
Learning Task 4. Solve the problem by applying the sum and product of roots
Delvig [45]

Answer:

<em>Thus, the dimensions of the metal plate are 10 dm and 8 dm.</em>

Step-by-step explanation:

For a quadratic equation:

x^2+bx+c=0

The sum of the roots is -b and the product is c. Note the leading coefficient is 1.

We know the perimeter of the rectangular metal plate is 36 dm and its area is 80 dm^2. Being L and W its dimensions, then:

P=2(L+W)=36

A=L.W=80

Note both formulas are closely related to the roots of the quadratic equation, we only need to adjust the data for the perimeter to be exactly the sum of L+W and not double of it.

Thus we use the semi perimeter instead as P/2=L+W=18

The quadratic equation is, then:

x^2-18x+80=0

Factoring by finding two numbers that add up to 18 and have a product of 80:

(x-10)(x-8)=0

The solutions to the equation are:

x=10, x=8

Thus, the dimensions of the metal plate are 10 dm and 8 dm.

6 0
3 years ago
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