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Roman55 [17]
3 years ago
14

One number is 33 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 3103

10​, find the numbers.
Mathematics
1 answer:
kherson [118]3 years ago
7 0
Create some expressions.

1# number: x

2# number: 33x

3# number: 100 + x


this all equals to 310310 when added so

x+33x+(x+100) = 310310

Solve what you know first then rearrange it.

34x + x + 100 = 310310

35x = 310310-100

35x = 310210

x = 310210/35

x = 8863.142857

Substitute the x into the expressions made and you'll find the 2# and 3# number. You've already found the 1# number since it's only x.
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298, 209, 129, 58, -4 continue the sequence
anastassius [24]

Answer:-

-93

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4 years ago
1/3 (6x - 9) + 3x - 8
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4 0
3 years ago
I’m confused on this one
expeople1 [14]

Hi,

Perimeter AEDCB=3*10+15+20=65 (units)

Ratio of the similitude r*15=21==>r=21/15=1.4

Perimeter RQPTS=65*1.4=91(units)

3 0
3 years ago
I don't know this. Its part of my math homework. 5^9x6/700(3^3)/90+600-9000/5000
Zigmanuir [339]

Answer:

5620.52142857

Step-by-step explanation:

Rounded 5620.52

Your Welcome : )

4 0
3 years ago
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