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Sphinxa [80]
3 years ago
5

How many real roots does the function f(x)=x^2-3x+4 have

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0
Since b^2 - 4ac = 9-16 < 0

There is no real root present. 
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\large\displaystyle\text{$\begin{gathered}\sf 7x-2(x+1)=6x+4 \end{gathered}$}

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Multiply both sides by −1.

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