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Lady bird [3.3K]
3 years ago
7

Which will result in a perfect square trinomial (3x-5) (-3x-5)?

Mathematics
1 answer:
makvit [3.9K]3 years ago
8 0

Answer:

-9x² + 25

Step-by-step explanation:

To solve, use FOIL. FOIL:

First

Outside

Inside

Last

Solve "First":

(3x)(-3x) = -9x²

Solve "Outside":

(3x)(-5) = -15x

Solve "Inside":

(-5)(-3x) = +15x

Solve "Last":

(-5)(-5) = +25

Combine like terms:

-9x² - 15x + 15x + 25

-9x² (-15x + 15x) + 25

-9x² + 25

-9x² + 25 is your answer.

~

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TASK 1
a) Data and frequency table are attached in picture #1.

b) The histogram is attached in picture #2

c) As the intervals increase the number of pieces of mail received, the frequency decreases, therefore we can say that are received few pieces of mail <span>are received more often.

TASK 2
a) The list of breeds and weights are reported in picture #3. 
</span>
In order to find the mean, sum up all the weights and divide by 9:
m = (<span>8 + 10 + 15 + 29 + 32 + 75 + 77 + 80 + <span>85) / 9 = 45.67 lbs

In order to find the median, you need to select the central value of your distribution: since you have 9 values, the central one will be in the fifth position:
M = 32 lbs

In order to find the mode, you need to select the value which shows more frequently: in this case, every value shows only once, therefore the mode cannot be determined.

The data are best described by the mean because they are almost symmetrically distributed between the least and the biggest values, while the median is more towards the small-weight side of the distribution.
 
b) In order to have an average of 250 lbs, the tenth dog should weight 2089 lbs.

Indeed, if the average is 250 lbs for 10 dogs, it means that the total sum of their weights is 250 × 10 = 2500 lbs. We know that the sum of the first 9 dogs is 411 lbs, therefore, the tenth dog should weight 2500 - 411 = 2089 lbs.

TASK 3
The city picked is Baltimore, the year 2017.
The table is attached in picture #4.
</span></span>
a) The box-and-whisker plot is attached in picture #5.

b) The median is the central value of the distribution, which is: <span> 
42.4, 45.3, 46.8 | 54.7, 57.6, 66.0 | 69.1,  76.5,  80.6 | 85.8, 87.8, 90.0 </span>
where we marked with a tally the quartiles.

Since we have 12 values, the median will be the average between the two central values:
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c) 7<span>5% of the temperatures are below 83.2 °F.
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3/4 </span>· (n + 1) = 3/4 · (12 + 1) = 3/4 <span>· 13 = 9.75
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q</span>₀.₇₅ = (80.6 + 85.8) / 2 = 83.2 °F

d) 7<span>5% of the temperatures are above 50.8 °F.
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e) Baltimore in 2017 had a median high temperature of 67.1 °F.
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Why isn't anyone answering this?
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