Let us say that:
a = ones
b = fives
c = twenties
So that the total money is:
1 * a + 5 * b + 20 * c = 229
=> a + 5b + 20c = 229 -->
eqtn 1
We are also given that:
c = a – 5 -->
eqtn 2
a + b + c = 30 -->
eqtn 3
Rewriting eqtn 3 in terms of b:
b = 30 – a – c
Plugging in eqtn 2 into this:
b = 30 – a – (a – 5)
b = 35 – 2a -->
eqtn 4
Plugging in eqtn 2 and 4 into eqtn 1:
a + 5(35 – 2a) + 20(a – 5) = 229
a + 175 – 10a + 20a – 100 = 229
11a = 154
a = 14
So,
b = 35 – 2a = 7
c = a – 5 = 9
Therefore there are 14 ones, 7 fives, and 9 twenties.
2. 64 = 2 × 2 × 2 × 2 × 2 × 2 2 |64
√64 = √2 × 2 × 2 × 2 × 2 × 2 2 |32
√64 = 2 × 2 × 2 2 |16
√64 = 2³ 2 |8
√64 = 8 2 |4
2 |2
3. No positive square root exists for -85 as it is a negative integer. The squares of a number is always positive.
4. 114 is not a perfect square. √114 = 10.677078252
5. √16 = 4
6. √105 = 10 (nearest)
7. √81 = 9
8. √14 = 4 (nearest)
9. √8 = 3 (nearest)
The answer is 1 by multiplying by itself
Let one of the numbers be x. The other number cab then be represented as 36-x (x+36-x = 36).
The product can then be represented as y = x(36-x) or y=36x-x2
The maximum or minimum is always on the axis of symmetry which has the formula x=-b/2a.
In our case, the axis of symmetry is -36/-2, so x=18.
If one number is 18 and the 2 numbers add to 36, the other number is 18 as well.
So the 2 numbers are 18 and 18 and the maximum product is 324,
