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3 years ago

7

NEED HELP PLS ASAP PLS

1 answer:

avanturin [10]3 years ago

7 0

Answer: (-1, 5)

Good luck!

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Find the product: <br><br> -2x(-y - 3x + 3)

cupoosta [38]

Answer:

$=2xy+6x^2-6x$

Step-by-step explanation:

$-2x\left(-y-3x+3\right)\\\mathrm{Distribute\:parentheses}\\=\left(-2x\right)\left(-y\right)+\left(-2x\right)\left(-3x\right)+\left(-2x\right)\cdot \:3\\\mathrm{Apply\:minus-plus\:rules}\\\left(-a\right)\left(-b\right)=ab,\:\:+\left(-a\right)=-a\\=2xy+2\cdot \:3xx-2\cdot \:3x\\\mathrm{Simplify}\:2xy+2\cdot \:3xx-2\cdot \:3x:\quad 2xy+6x^2-6x\\2xy+2\cdot \:3xx-2\cdot \:3x\\2\cdot \:3xx=6x^2\\2\cdot \:3x=6x\\=2xy+6x^2-6x$

8 0

3 years ago

Read 2 more answers

Jerome will also order t-shirt for the volunteers he will both adults and child sized t-shirt adults t-shirt are $5;and child t-

Daniel [21]

<h3><u>The two inequalities are:</u></h3>

$a\geq 200\\\\5a + 2.50c\leq 1500$

<h3><u>Solution:</u></h3>

Let "a" be the number of adult sized t shirts

Let "c" be the number of child sized t shirts

Given that,

Each Adult sized t shirts = $ 5

Each child sized t shirts = $ 2.50

<h3><u>Jerome need at least 200 adults t-shirt</u></h3>

Therefore,

$a\geq 200$

Here, we used "greater than or equal to" symbol, since he needs atleast 200 adult t-shirts

<h3><u>Jerome will spend no more than $1500 on t-shirt</u></h3>

Therefore,

$5a + 2.50c\leq 1500$

Here we used, "less than or equal to" symbol, since he will not spend more than 1500

Thus the two inequalities are found

3 0

3 years ago

Do these side lengths make a triangle 8, 2, 12,

Paul [167]

Answer:

22

Step-by-step explanation:

3 0

3 years ago

A bag contains 4 red marbles, 3 white marbles, and 7 blue marbles. You pick a marble without looking. What is the probability of

zmey [24]

Answer:

3/14

Step-by-step explanation:

You add all the marbles to get your total/denominator then take the white marbles and that is the numorator.

6 0

3 years ago

URGENT !!! 25 POINTS AND BRAINIEST FOR CORRECT ANSWER!!!

fenix001 [56]

Given a polynomial p(x) with leading coefficient $a$ and solutions $x_1,x_2,\ldots,x_n$ , we have

$p(x)=a(x-x_1)(x-x_2)\ldots(x-x_n)$

That's why we have to find the solutions first. We complete the square by adding 3 to both sides:

$x^2-2x-2=0 \iff (x^2-2x-2)+3=3 \iff x^2-2x+1=3 \iff (x-1)^2=3$

From here, we continue by taking the square root of both sides:

$x-1=\pm 3 \iff x=1\pm\sqrt{3}$

So, the two solutions are

$x_1=1+\sqrt{3},\quad x_2=1-\sqrt{3}$

Which yields the factorization

$x^2-2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

3 0

3 years ago