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LenKa [72]
3 years ago
11

Slope=1;y-intercept=-4 step by step help?

Mathematics
1 answer:
kvasek [131]3 years ago
4 0

Answer: 4

Step-by-step explanation:

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The gas tank of the truck holds 30 gallons the gas tank of a passenger car holds 50% less how many gallons does it hold?
love history [14]

Answer:

15 gallons

Step-by-step explanation:

To find how much the passenger car holds, we need to first find what 50% of the trucks gas tank holds.

Truck Gas Tank = 30 gallons

Now we find how much 50% of 30 is:

50% = 0.50

Total = 30 x 0.50

Total = 15 Gallons

So the passenger car holds 15 gallons of gas.

4 0
3 years ago
Please help me with math thanks
Korvikt [17]
Given that a room is shaped like a golden rectangle, and the length is 29 ft with the ratio of  golden rectangle being (1+√5):2, thus the width of the room will be:
ratio of golden triangle=(length if the room)/(width of the room)
let the width be x
thus plugging the values in the expression we get:
29/x=(1+√5)/2
solving for x we get:
x/29=2/(1+√5)
thus
x=(29×2)/(1+√5)
answer is:
x=58/(1+√5)
or
 byrationalizing the denominator by multiplying both the numerator and the denominator by (1-√5)
58/(1+√5)×(1-√5)/(1-√5)
=[58(1-√5)]/1-5
=(58√5-58)/4
7 0
3 years ago
A ratio equivalent to 2:5 is 2 :10
azamat
False... a ratio equivalent to 2:5 is 4:10

2/5 × 2/2 = 4/10
8 0
3 years ago
(03.01)<br> The domain of the following relation R {(3,-2), (1, 2), (-1,-4), (-1, 2)} is
Anna35 [415]

The domain is set of x-value.

Therefore, the domain of the relation Domain of R = {3,1,-1}

6 0
3 years ago
in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin
Alborosie

<u>Answer-</u>

<em>The probability of winning on the first roll is </em><em>0.22</em>

<u>Solution-</u>

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

|S|=6^2=36

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

|E|=56

\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

|F|=2

\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}

Now,

P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22

8 0
4 years ago
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