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alex41 [277]
3 years ago
9

What is 15/8 as a mixed number

Mathematics
2 answers:
9966 [12]3 years ago
6 0
It would be equal to 1 7/8
romanna [79]3 years ago
3 0
1 and 3/4 would be the answer :)
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an arts academy requires there to be 3 teachers for every 75 students and 6 tutors for every 72 students. How many students does
Zinaida [17]
Each teacher has 25 students. 75/3 would be 25. I hope this helped!
5 0
3 years ago
4/8 - 3/10 pa answer ulii
marysya [2.9K]

Answer:

1/5

Step-by-step explanation:

4/8-3/10=1/5

8 0
2 years ago
Read 2 more answers
Evaluate the expression when X= -2 x^2 + 9x + 3
TiliK225 [7]

Answer:

-11

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

x² + 9x + 3

x = -2

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                                                                                                  (-2)² + 9(-2) + 3
  2. Exponents:                                                                                                        4 + 9(-2) + 3
  3. Multiply:                                                                                                             4 - 18 + 3
  4. Subtract:                                                                                                            -14 + 3
  5. Add:                                                                                                                   -11
3 0
3 years ago
Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF
drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD    and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

\therefore m\angle A = m\angle B ⇒1

And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

m\angle F=m\angle E=90\° ⇒2

Now In △ABE and △CBF

∠A = ∠C   (from 1)

∠E = ∠F    (from 2)

So by A.A. similarity postulate;

△ABE∼△CBF

7 0
3 years ago
2x + (-x) + 3 + (-2)
meriva

Answer:

-x+3

Step-by-step explanation:

hope this helps

4 0
3 years ago
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