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disa [49]
4 years ago
12

Can someone please help me?? I don't understand this at all...

Mathematics
2 answers:
Lyrx [107]4 years ago
5 0
The manager would be correct.

A range of 62 players (16-72) is very inconsistent as that is a very large gap!

Hope this helps! :)
Artemon [7]4 years ago
4 0
Here's something I learned, if that's a go math text book the answers are always in the last couple pages of the book
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The size of a rectangular computer monitor is determined by the length of its diagonal. If a
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Answer:

42 inches

Step-by-step explanation:

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4 years ago
Jane and Jill collect yo-yo’s. The ratio of the number of Jane’s yo-yo’s to the number of Jill’s yo-yo’s is 5:4. If Jane will gi
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The girls will have 135 yo-yo's together!

5 0
3 years ago
Read 2 more answers
WILL MARK B!<br> Please I need help I have a quiz
MArishka [77]

Answer:

a) 2x² - x + 3 = x(2x + 1) - 2x

<=> 2x² - x + 3 = 2x² + x - 2x

<=> 3 - x = - x

<=> 3 = 0

=> no solution

b) x/2 - x/3 - x/4 = 1/12

\frac{6x}{12}  -  \frac{4x}{12}  -  \frac{3x}{12}  =  \frac{1}{12}  \\  \\  \frac{ - x}{12}  =  \frac{1}{12}  \\  \\  =  >  - x = 1 \\  \\  \\  <  =  > x = 1

=> the euqation has the solution x = 1

c) |x - 5| = 2|x|

=> x - 5 = 2x

or x - 5 = -2x

<=> x = -5

or 3x = 5

<=> x = -5

x = -5or x = 5/3

d) defined conditions: 2 - x 》 0

<=> x 《 2

we have:

\sqrt{x + 4}  = 2 - x \\  <  =  > x + 4 = (2 - x) {}^{2}   \\  <  =  > x + 4 =  {x}^{2}  - 4x + 4 \\  <  =  >  {x}^{2}  - 5x = 0 \\  <  =  > x(x - 5) = 0 \\

<=> x = 0 (because x 《 2)

e)

\sqrt{5}  =  \frac{1}{25 {}^{x} }  \\   =  > 5 =  \frac{1}{25 {}^{2x} }  \\  <  =  > 5.25 {}^{2x}  = 1  \\ <  =  >  5.5 {}^{4x}  = 1 \\  <  =  > 5 {}^{4x + 1}  = 1 \\  =  > 4x + 1 = 0

<=> x = -1/4

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3 years ago
Read 2 more answers
alice started at the origin and moved to the left and then down to plot a point. which quadrant and which possible point did ali
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OK

Step-by-step explanation:

LOL SO WHAT I . DID

IS ik the qudrents and just ask siri maybe she will help but i got qudrent 3

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3 years ago
Drag and drop the correct angle measures onto the diagram!!! HELP THIS IS URGENT
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I think this is the answer for your problem.
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