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Oxana [17]
2 years ago
13

How many ways can an employer send 3 employees to a job fair if she has 11 employees?

Mathematics
1 answer:
algol132 years ago
6 0

We have to find the number of ways an employer send 3 employees to a job fair if she has 11 employees.

This is the problem from combination.

The formula for combination is given by

^nC_r= \frac{n!}{r!(n-r)!}

Here, n= 11, r= 3

Therefore, total number of ways is given by

^{11}C_3= \frac{11!}{3!(11-3)!}\\
\\
=\frac{11!}{3!8!}\\
\\
=\frac{8!\times 9 \times 10 \times 11}{3!8!}\\
\\
=\frac{9 \times 10 \times 11}{6}\\
\\
=165

A is the correct option.


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What is the vertex form, f(x) = a(x − h)2 + k, for a parabola that passes through the point (1, −7) and has (2, 3) as its vertex
kondaur [170]

Answer:

Vertex form: f(x) = -10(x − 2)^2 + 3

Standard form: y = -10x^2 + 40x - 37

Step-by-step explanation:

h and k are the vertex coordinates

Substitute them in the vertex form equation:

f(x) = a(x − 2)^2 + 3

Calculate "a" by replacing "f(x)" with -7 and "x" with 1:

-7 = a(1 − 2)^2 + 3

Simplify:

-7 = a(1 − 2)^2 + 3

-7 = a(-1)^2 + 3

-7 = a + 3

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Replace a to get the final vertex form equation:

f(x) = -10(x − 2)^2 + 3

Convert to standard form:

y = -10(x − 2)^2 + 3

Expand using binomial theorem:

y = -10(x^2 − 4x + 4) + 3

Simplify:

y = -10x^2 + 40x - 40 + 3

y = -10x^2 + 40x - 37

6 0
3 years ago
The three angle bisectors of ΔABC intersect at point P. Point P is the
lisabon 2012 [21]
<h3>Answer: C) incenter</h3>

========================================

Explanation:

If you were to intersect the angle bisectors (at least two of them), then you would locate the incenter. The incenter is the center of the incircle which is a circle where it is as large as possible, but does not spill over and outside the triangle. Therefore this circle fits snugly inside the triangle.

--------------

extra notes:

* The centroid is found by intersecting at least two median lines

* The circumcenter is found by intersecting at least two perpendicular bisector lines

* The orthocenter is found by intersecting at least two altitude lines

* The incenter is always inside the triangle; hence the "in" as part of the name. The centroid shares this property as well because the medians are completely contained within any triangle. The other two centers aren't always guaranteed to be inside the triangle.

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From the data, the highest to lowest value can be written as

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