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Darina [25.2K]
3 years ago
8

What is 87.92 rounded to the nearest tenth

Mathematics
2 answers:
alex41 [277]3 years ago
8 0

Answer:

87.92 rounded to the nearest tenth would be 87.9 because you wouldn't round up unless the number after the 9 was 5 or higher.

Step-by-step explanation:

Ganezh [65]3 years ago
3 0

Step-by-step explanation:

87.9

......

hope it helps!

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Please help me with this problem? Thanks :)
Alexandra [31]
What does this mean I don't understand sorry I can't help!
3 0
4 years ago
Mrs. Simmons gave a history test worth 92 points. There were only two types of questions on it: 2-point true/false questions and
SVETLANKA909090 [29]

Answer:

There are 8 true/false questions and 26  fill-in-the-blank questions.

Step-by-step explanation:

Let "t" be the number of 2-point true/false questions and "f" the number of 5-point fill-in-the-blank questions.

Mrs. Simmons gave a history test worth 92 points. Symbollically,

2 t + 5 f = 92   [1]

There were a total of 34 questions in the test. Symbollicaly,

t + f = 34

t = 34 - f   [2]

If we replace [2] in 1, we get

2 (34 - f) + 5 f = 92

68 - 2 f + 5 f = 92

3 f = 24

f = 8

We replace f = 8 in [2],

t = 34 - 8 = 26

There are 8 true/false questions and 26  fill-in-the-blank questions.

7 0
3 years ago
Someone plz help me <br> I will give brainliest
umka2103 [35]

Answer:

10 days

Step-by-step explanation:

2/.2=10

3 0
3 years ago
Read 2 more answers
POSSIBLE OUTCOMES!!!
Ganezh [65]

The probability of drawing two blue marbles if the first marble is not replaced is 1/5

<h3>How to determine the probabilities?</h3>

<u>The probability of tossing a head and drawing a red marble</u>

The given parameters are:

White = 1

Blue =3

Red = 2

Total = 6

The probability of a head is

P(Head)= 1/2

The probability of drawing a red marble is

P(Red)= 2/6 = 1/3

The required probability is

P = P(Head) * P(Red)

This gives

P = 1/2 * 1/3

P =1/6

<u>The probability of drawing two blue marbles if the first marble is not replaced.</u>

Here, we have:

P(B1) = 3/6 = 1/2

P(B2) = 2/5

The required probability is

P = P(B1) * P(B2)

This gives

P = 1/2 * 2/5

P =1/5

Hence, the probability of drawing two blue marbles if the first marble is not replaced is 1/5

Read more about probability at:

brainly.com/question/24756209

#SPJ1

5 0
2 years ago
PLEASE HELP DUE 3 DAYS. WORTH 45 POINTS!
saul85 [17]
It would be 1.1 miles
5 0
4 years ago
Read 2 more answers
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