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Kaylis [27]
3 years ago
5

Can someone plz help me with #2 and #6 plz thank oyu

Mathematics
1 answer:
Marat540 [252]3 years ago
3 0

Answer:

njbrdjbbgdbjbfjfj

Step-by-step explanation:

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What equation is graphed in this figure?
bixtya [17]
The answer is C

Here is the process, hope it helps!
y+2=-3/2(x-2)
y+2=-3/2x+3
y=-3/2x+1

4 0
3 years ago
Please help im so confused lol
BARSIC [14]

Answer:

1. Percent

2. Number

Step-by-step explanation:

6 0
3 years ago
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Dear Math Helper, You write a great column, and I hope you stay around for years to come. I run a small boarding school. We are
inessss [21]
The easiest way to determine the score is to use a calculator or spreadsheet and the appropriate probability function.

If you want the top 10%, the score corresponds to the 90th percentile. That score is 316.

If you want the top 15%, the score corresponds to the 85th percentile. That score is 313.

5 0
3 years ago
How to do composition of functions​
KengaRu [80]
<h2><u><em>If you rather have the link to get this info lmk!!</em></u></h2>

Example: f(x) = 2x+3 and g(x) = x2

"x" is just a placeholder. To avoid confusion let's just call it "input":

f(input) = 2(input)+3

g(input) = (input)2

Let's start:

(g º f)(x) = g(f(x))

First we apply f, then apply g to that result:

Function Composition - (g º f)(x) = (2x+3)2

What if we reverse the order of f and g?

(f º g)(x) = f(g(x))

First we apply g, then apply f to that result:

Function Composition - (f º g)(x) = 2x2+3

We get a different result!  When we reverse the order the result is rarely the same.  So be careful which function comes first.

<h2 />
5 0
3 years ago
Determine whether the set, together with the indicated operations, is a vector space. If it is not, then identify one of the vec
Mama L [17]

Answer:

The answer to the question are

(B) The set is not a vector space because it is not closed under addition. and

(D) The set is not a vector space because an additive inverse does not exist.

Step-by-step explanation:

To be able to identify the possible things that can affect a possible vector space one would have to practice on several exercises.

The vector space axioms that failed are as follows

(B) The set is not a vector space because it is not closed under addition.

(2·x⁸ + 3·x) + (-2·x⁸ +x) = 4·x which is not an eighth degree polynomial

(D) The set is not a vector space because an additive inverse does not exist.

There is no eight degree polynomial  = 0

The axioms for real vector space are

  • Addition: Possibility of forming the sum  x+y which is in X from elements  x and y which are also in X
  • Inverse: Possibility of forming an inverse -x which is in X from an element x which is in X
  • Scalar multiplication: The possibility of forming multiplication between an element x in X and a real number c of which the product cx is also an element of X
7 0
4 years ago
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