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Korolek [52]
3 years ago
9

How to do composition of functions​

Mathematics
1 answer:
KengaRu [80]3 years ago
5 0
<h2><u><em>If you rather have the link to get this info lmk!!</em></u></h2>

Example: f(x) = 2x+3 and g(x) = x2

"x" is just a placeholder. To avoid confusion let's just call it "input":

f(input) = 2(input)+3

g(input) = (input)2

Let's start:

(g º f)(x) = g(f(x))

First we apply f, then apply g to that result:

Function Composition - (g º f)(x) = (2x+3)2

What if we reverse the order of f and g?

(f º g)(x) = f(g(x))

First we apply g, then apply f to that result:

Function Composition - (f º g)(x) = 2x2+3

We get a different result!  When we reverse the order the result is rarely the same.  So be careful which function comes first.

<h2 />
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Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
scoray [572]

Answer: 12

Step-by-step explanation:

You can multiply by 12 because to get rid of the fractions all terms should be divided by the LCM (ie the smallest multiple that is exactly divisible by 2, 4 and 3)

Multiples of 3 = 3, 6, 9, 12

Multiples of 4 = 4, 8, 12, 16

Multiples of 2 = 2, 4, 6, 8, 10, 12

Therefore the fractions should be multiplied by 12

5 0
3 years ago
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Esi says that the value of z when z^2 = 80 does not belong in either of these categories since z must be greater than 8.
Anettt [7]

Answer:

9

Step-by-step explanation:

if z=8 then z^2 would be 64, which is not equal to 80

iz z=9 then z^2 would be 81, which is closer to 80 than 64

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7 0
3 years ago
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Construct a polynomial function with the following properties: third degree, only real coefficients, −3 and 3+i are two of the z
irina [24]

Answer:

\boxed{-3(x+3)(x^2-6x+10)}

Step-by-step explanation:

Hello,

As the polynomial has only real coefficients, it means that 3-i is a zero too, because we apply the Conjugate Zeros Theorem.

It means that we can write the expression as below, k being a real number that we will have to identify.

k(x+3)(x-3-i)(x-3+i)=k(x+3)((x-3)^2-i^2)\\\\=k(x+3)(x^2-6x+9+1)\\\\=k(x+3)(x^2-6x+10)

And for x = 0, y = -90 so we can write

-90=k*3*10, meaning that k=-3

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
How to find the area of a regular hexagon with a radius of 12 inches? Please help
Volgvan
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1 year ago
I don’t understand? How do you do numbers 3 and 4?
katovenus [111]
This is the answer, hope this helps you

7 0
3 years ago
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