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OLEGan [10]
3 years ago
5

Determine whether the set, together with the indicated operations, is a vector space. If it is not, then identify one of the vec

tor space axioms that fails. The set of all eighth-degree polynomials with the standard operations.
(A) The set is a vector space.
(B) The set is not a vector space because it is not closed under addition.
(C) The set is not a vector space because the associative property of addition is not satisfied
(D) The set is not a vector space because an additive inverse does not exist.
(E) The set is not a vector space because the distributive property of scalar multiplication is not satisfied.
Mathematics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

The answer to the question are

(B) The set is not a vector space because it is not closed under addition. and

(D) The set is not a vector space because an additive inverse does not exist.

Step-by-step explanation:

To be able to identify the possible things that can affect a possible vector space one would have to practice on several exercises.

The vector space axioms that failed are as follows

(B) The set is not a vector space because it is not closed under addition.

(2·x⁸ + 3·x) + (-2·x⁸ +x) = 4·x which is not an eighth degree polynomial

(D) The set is not a vector space because an additive inverse does not exist.

There is no eight degree polynomial  = 0

The axioms for real vector space are

  • Addition: Possibility of forming the sum  x+y which is in X from elements  x and y which are also in X
  • Inverse: Possibility of forming an inverse -x which is in X from an element x which is in X
  • Scalar multiplication: The possibility of forming multiplication between an element x in X and a real number c of which the product cx is also an element of X
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Answer:

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C. No, the solution is (0,-16)

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Step-by-step explanation:

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