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3 years ago

10

Your grades on three exams are 80, 93, and 91. What grade do you need on the next exam to have an average of 88 on all four exam

s?

1 answer:

PolarNik [594]3 years ago

8 0

Answer:

the first score is 90

the second score is 95 and the third score u need is 95

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So midpoint of segment joining B and C is ( 11/2, - 13/2)

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Which values of k would cause this system of equations to have no solution? Check all that apply.

xeze [42]

Answer:

x= -2y/3

-4y+4y=14

0y= 14

This has no solution.

Step-by-step explanation:

Answer In cases of two equations having two unknown variables the simultaneous method of solving the equations is adopted.

Supposing “0” as the value of “k” we will have the equation as 3x+2y=0

Then separating variable x will give, x= -2y/3

Substituting the value of x into the first equation that is: 6x + 4y = 14

6(-2y/3)+4y=14

Expanding this we get: 6(-2y/3)+4y=14

-4y+4y=14

0y= 14

Thus, no solution.

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3 years ago

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3 years ago

The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow

Reika [66]

If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now $\bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
0=w^2\\\\
0=\frac{3w^2-6000000}{w^2}
\end{cases}$

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the $0=w^2\implies 0=w$ so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

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3 years ago