Answer:

For this case we can conclude that with 98% of confidence the true proportion of Drosophila in a population would be between 0.34 and 0.38.
But that doesn't means that we have 98% of PROBABILITY that the true proportion would be between 0.34 and 0.38, because we are constructing a confidence interval with sample data and we can't analyze this using probability.
Then the best answer is:
2. False
Step-by-step explanation:
For this case we have a confidence interval for the proportion of Drosophila in a population with mutation Adh-F to be given by:

For this case we can conclude that with 98% of confidence the true proportion of Drosophila in a population would be between 0.34 and 0.38.
But that doesn't means that we have 98% of PROBABILITY that the true proportion would be between 0.34 and 0.38, because we are constructing a confidence interval with sample data and we can't analyze this using probability.
Then the best answer is:
2. False
Answer:
The first one is 90, and the second one is 150
Explanation:
40% of 90 is 36, and
40% of 150 is 60.
Answer:
25/100
Step-by-step explanation:
Given:
Overhead cost = 34,816
Production cost per lawn mower = 388
Average cost per lawn mower = 660
Total Production cost + Overhead Cost = Total Cost
Total Cost ÷ # of lawn mowers produced = Average cost per lawnmower
Let x be the number of lawn mowers produced:
(388x + 34,816)/x = 660
x((388x + 34,816)/x) = x * 660
388x + 34,816 = 660x
34,816 = 660x - 388x
34,816 = 272x
34,816/272 = 272x/272
128 = x
There are 128 lawnmowers manufactured.
To check:
388x + 34,816 = total production cost.
388(128) + 34,816 = 49,664 + 34,816 = 84,480
84,480 ÷ 128 = 660 ave cost per unit