Answer:
C
Step-by-step explanation:
Since every side of ΔABC is dilated by 3, or triple the size
We multiply every length of ΔABC by 3
But the length of DF and FG are already done for us but DG is not, which is essential to finding the answer
7 x 3 = 21
DG = 21
5/7 = 15/21
5 ÷ 7 = 0.71
15/21 = 0.71
5/7 = 15/21
Step One
Find the sum of the fractions for Monday and Tuesday
1/2 + 2/5
The common denominator for these 2 days is 10
1/2: 1*5/(2*5) = 5/10
2/5:2*2/(2*5) = 4/10
Add these two equivalent fractions together.
5/10 + 4/10 = 9/10
The first 2 days resulted in 9/10 of the shed being completed.
Step Two
Find out how much (in terms of fractions) is left of the shed.
Let the whole shed = 1
Let what has been done = 9/10
What remains is 1 - 9/10 = 1/10
Answer: 1/10 of the shed needs to be done
Answer: B. 2=3x+10x^2
Step-by-step explanation:
The expression means the quadratic function equation.
B = 10x^2 + 3x -2 = 0
the equation is [-b ±√(b^2 -4ac)]/2a
b should be +3 to become -3 when it is plugged into the equation, and 'a' should be 10, and c should be -2.
Answer:
Step-by-step explanation:
c + a = 342 ..................... <em>(1)</em>
5c + 12a = 2550 ........... <em>(2)</em>
- 5 × <em>(1)</em> + <em>(2)</em>
7a = 840
<em>a = 120</em>
<em>c</em> = 342 - 120 <em>= 222</em>
