A 1 = 57, a 2 = 61, a 3 = 65 ( arithmetic sequence )
a n = a 1 + ( n - 1 ) d
a 2 = a 1 + d
61 = 57 + d
d = 61 - 57
d = 4
a 9 = 57 + 8 * 4 = 57 + 36 = 93
Answer: Her score on the 9th assessment will be 93 points.
- Midpoint formula is
.
<h3>19.</h3>
So starting with this one, we will be solving for the coordinates of the unknown endpoint separately. Starting with the x-coordinate, since we know that the midpoint x-coordinate is 5 and the x-coordinate of N is 2, our equation is set up as such:
From here we can solve for the x-coordinate of Q.
Firstly, multiply both sides by 2: 
Next, subtract both sides by 2 and your x-coordinate is 
With finding the y-coordinate, it's a similar process as with the x-coordinate except that we are using the y-coordinates of the midpoint and endpoint N.

<u>Putting it together, the missing endpoint is (8,4).</u>
<em>(The process is pretty much the same with the other problems, so I'll go through them real quickly.)</em>
<h3>20.</h3>


<u>The missing endpoint is (7,2).</u>
<h3>21.</h3>


<u>The missing endpoint is (-5,1).</u>
Answer:
other person is correct
Step-by-step explanation:
Answer:
This is simple,
Step-by-step explanation:
If the bus costs 200$ and the fair charges 4$ per students that means you have to do this:
300$ budget - 200 of the bus = 100$ left
and if $4 per student:
100 divided by 4 = 25
she can take 25 students
Hope this helps!
the blue dotted line means the parent function was shifted 2 units down
so the graph is g(x) = (1/3)^x-2
Answer would be A.