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LuckyWell [14K]
3 years ago
13

Pleaseeee helppppppp​

Physics
2 answers:
vredina [299]3 years ago
7 0

Answer:

the vertical acceleration is 9.8 m/s,

downward and no horizontal acceleration..

Mnenie [13.5K]3 years ago
6 0

Answer:

9.8 m/s2

Explanation:

that's the correct answer

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Freddie drives his car 10 km North. He stops for gas and then drives 5 km South.
fgiga [73]

Answer:

5 km

Explanation:

displacement is the straight line distance from a particular point. since north and south are in opposite directions, it means that he has taken a u-turn

thus, 10 - 5 = 5km displacement

4 0
3 years ago
How can gases have such a large impact on earths atmosphere
kozerog [31]

Answer:

well, the air in our atmosphere stays there and nothing can get past the last layer. Think of is as a car. if there gets to be too much gas in it, it can harm you. I would also say it is one of the causes of global warming. Also air pollution is a big problem.

Explanation:

8 0
3 years ago
Describe the role of observations in scientific endeavor and explain the characteristics of good observations.
koban [17]
Observations are used in order to collect data and record a variety of interesting or useful key points about the subject or specimen in observation. These observations, if made well, can be recorded and used to supplement a hypothesis. 
3 0
3 years ago
Water drops fall from the edge of a roof at a steady rate. a fifth drop starts to fall just as the first drop hits the ground. a
Alchen [17]

The height of the roof is <u>3.57m</u>

Let the drops fall at a rate of 1 drop per t seconds. The first drop takes 5t seconds to reach the ground. The second drop takes 4t seconds to reach the bottom of the 1.00 m window, while the 3rd drop takes 3t s to reach the top of the window.

Calculate the distances traveled by the second and the third drops s₂ and s₃, which start from rest from the roof of the building.

s_2=\frac{1}{2} g(4t)^2=8gt^2\\  s_3=\frac{1}{2} g(3t)^2=(4.5)gt^2

The length of the window s is given by,

s=s_2-s_3\\ (1.00 m)=8gt^2-4.5gt^2=3.5gt^2\\ t^2=\frac{1.00 m}{(3.5)(9.8m/s^2)} =0.02915s^2

The first drop is at the bottom and it takes 5t seconds to reach down.

The height of the roof h is the distance traveled by the first drop and is given by,

h=\frac{1}{2} g(5t)^2=\frac{25t^2}{2g} =\frac{25(0.02915s^2)}{2(9.8m/s^2)} =3.57 m

the height of the roof is 3.57 m



8 0
4 years ago
Read 2 more answers
A 0.05-m3 rigid tank initially contains refrigerant-134a at 0.8 MPa and 100 percent quality. The tank is connected by a valve to
lesya692 [45]

Answer:

A= 203 KJ

B= 54 Kg

Explanation:

The initial specific volumes and internal energies are obtained from A-12 for a given pressure and state. The enthalpy of the refrigerant in the supply line is determined using the saturated liquid approximation for the given temperature with data from A-11. The mass that has entered the tank is:

Δm = m₂ – m₁

= V(1/α₂ – 1/α₁)

= 0.05 (1/0.0008935 – 1/ 0.025645)Kg

= 54Kg

The heat transfer is obtained from the energy balance:

ΔU= m_i_n h_i_n+  Q_n_e_t

m₂u₂ – m₁u₂ = m_i_nh_i_n + Q_n_e_t

Q_n_e_t= m₂u₂ – m₁u₁ – m_i_n

= V/α₂u₂ - V/α₁u₁ – m_i_n

=(0.05/0.0008935 . 116.72 – 0.05/0.025645 . 246.82 – 54.108.28) Kj

= 203 KJ

8 0
3 years ago
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