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OverLord2011 [107]

3 years ago

10

A water balloon was dropped from a high window and struck its target 1.1 seconds later. If the balloon left the person's hand at

-5 meters/sec what was the velocity on impact?

2 answers:

valkas [14]3 years ago

8 0

-5.5 is the answer to the question

Galina-37 [17]3 years ago

6 0

-5.5 is the correct answer for ur question

hope this helps u

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Describes the relationship between the free energy change, the reaction quotient, and the equilibrium constant.

LUCKY_DIMON [66]

<u>Explanation:</u>

Reaction quotient is defined as the ratio of the concentration of the products and reactants of a reaction at any point of time with respect to some unit. It is represented by the symbol <em>Q</em>.

The ratio of the concentration of products and reactants of a reaction in equilibrium with respect to some unit is said to be equilibrium constant expression. It is represented by the symbol <em>K</em>.

The relationship between Gibbs free energy change and reaction quotient of the reaction is:

$\Delta G=\Delta G^o+RT ln Q$ ......(1)

where,

$\Delta G$ = Gibbs free energy change

$\Delta G^o$ = Standard Gibbs free energy change

R = Gas constant

T = Temperature

At equilibrium, the free energy change of the reaction becomes 0 and standard Gibbs free energy change can be related to the equilibrium constant by the equation:

$\Delta G^o=-RT ln Q$ ...(2)

4 0

3 years ago

A baseball is thrown at a 28° angle and an initial velocity of 70 m/s. Assume no air resistance. What is the vertical component

icang [17]

Answer:

answer is 61.8 m/s; 32.9

l am not sure

3 0

3 years ago

Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This

vova2212 [387]

Answer:

$1.554\times 10^{32}\ \text{kg}$

Explanation:

M = Mass of each star

T = Time period = 15.5 days

v = Orbital velocity = 230 km/s

G = Gravitational constant = $6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2$

Radius of orbit is given by

$R=\dfrac{vT}{2\pi}$

We have the relation

$\dfrac{Mv^2}{R}=\dfrac{GM^2}{(2R)^2}\\\Rightarrow M=\dfrac{4Rv^2}{G}\\\Rightarrow M=\dfrac{4\dfrac{vT}{2\pi}v^2}{G}\\\Rightarrow M=\dfrac{2v^3T}{\pi G}\\\Rightarrow M=\dfrac{2\times 230000^3\times 15.5\times 24\times 60\times 60}{\pi\times 6.674\times 10^{-11}}\\\Rightarrow M=1.554\times 10^{32}\ \text{kg}$

The mass of each star is $1.554\times 10^{32}\ \text{kg}$

6 0

3 years ago

Momentum for a system can be conserved in one direction while not being conserved in another. What is the anglebetween the direc

katrin [286]

Answer:

90°

Explanation:

The angle will be 90° when momentum for a system can be conserved in one direction while not being conserved in another.

The example can be

If we apply force on an object horizontally in west direction, then as in other direction south or north we cannot apply the principal of momentum conservation.

5 0

3 years ago

Which part of an atom is mostly empty space?

Veronika [31]

Answer:

The electron cloud is mostly empty space

7 0

3 years ago