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andreev551 [17]
3 years ago
7

And air rifle pellet of mass 2 g Is fired into a block of modelling clay mounted on a model railway track. The trunk and modelli

ng clay have a mass of 0.1 kg the truck moves off after the pellet hits the modelling clay with an initial velocity of 0.8 m/s. State the momentum of the pallet just before it hits the modelling clay
Physics
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

0.0816 kgm/s

Explanation:

From the question,

Momentum of the pellet just before it hits the modelling clay is = (mass of the pellet+ mass of the truck clay)×initial velocity of pellet.

P =(M+m)u...................... Equation 1

Where P =  initial momentum of the pellet, m = mass of the pellet, u = initial speed of the pillet, M = mass of the truck

Given: m = 2 g = 2/1000 kg = 0.002 kg, u = 0.8 m/s, M = 0.1 kg

Substitute these values into equation 1

P = (0.002+0.1)0.8

P = (0.102)0.8

P = 0.0816 kgm/s

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Given:

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v'=u'-g.t'

0=10.259-9.8\times t'

t'=1.0469\ s

<u>We observe that </u>t>t'<u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

\Delta t=t-t'

\Delta t=1.0642-1.0469

\Delta t=0.0173\ s

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