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hodyreva [135]
3 years ago
6

Someone help me please

Physics
2 answers:
sp2606 [1]3 years ago
8 0

Im not fully sure about this. But i believe its A.

For Example: The constant pull of gravity on the moon is way different then on the earth, same with the acceleration of gravity. This is why objects float more on the moon.

-Seth

Alekssandra [29.7K]3 years ago
8 0

I believe this is A. aswell, i may be incorrect. good luck on your test :)

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How far can a car traveling at a rate of 40 kilometer per hour travelbin 2 1/2 hours
CaHeK987 [17]
90 kilometers because you need to multiply 40 by 2 and then you get 80 and finally you add 10 and get 90 kilometers
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3 years ago
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Help with 7,8,9 please!!
Marysya12 [62]

# 7 the answer is 4) because you need opposites in order to attract

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# 9  the answer is 4) because the comb dose collect negative charges from the hair in order to make the hair have positive charge.


Hope this helped : )

4 0
3 years ago
Two objects of same material are travelling near you. Object A is a 1.1 kg mass traveling 10.2 m/s; object B is a 2 kg mass trav
Gnoma [55]

Answer:

Object A

Explanation:

The object that would make you feel worse if you're hit by it is the object possessing the highest momentum. Thus, we need to find the momentum of the two objects.

Momentum of an object is the product of its mass and that of it's velocity. Momentum is given by the formula

P = M * V, where

P = momentum

M = mass of the object

V = velocity of the object

Now, solving for object A, we have

P(a) = 1.1 * 10.2

P(a) = 11.22 kgm/s

And then, solving for object B, we have

P(b) = 2 * 5

P(b) = 10 kgm/s

The object when the highest momentum is object A, and thus would make you feel worse when hit by it

3 0
3 years ago
Please help i would really appreciate it
Verdich [7]

Answer:

THE MINIONSSSSSSS AYEEEEE

Explanation:

4 0
3 years ago
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To develop muscle tone, a woman lifts a 2.50 kg weight held in her hand. She uses her biceps muscle to flex the lower arm throug
Romashka [77]

To solve this problem we will use the concepts related to Torque as a function of the Force in proportion to the radius to which it is applied. In turn, we will use the concepts of energy expressed as Work, and which is described as the Torque's rate of change in proportion to angular displacement:

\tau = Fr

Where,

F = Force

r = Radius

Replacing we have that,

\tau = Fr

\tau = 21cm (\frac{1m}{100cm})* 550N

\tau = 11.55Nm

The moment of inertia is given by 2.5kg of the weight in hand by the distance squared to the joint of the body of 24 cm, therefore

I = 0.25Kg\cdot m^2 +(2.5kg)(0.24m)^2

I = 0.394kg\cdot m^2

Finally, angular acceleration is a result of the expression of torque by inertia, therefore

\tau = I\alpha \rightarrow \alpha = \frac{\tau}{I}

\alpha = \frac{11.55}{0.394}

\alpha = 29.3 rad/s^2

PART B)

The work done is equivalent to the torque applied by the distance traveled by 60 °° in radians (\pi / 3), therefore

W = \tau \theta

W = 11.5* \frac{\pi}{3}

W = 12.09J

4 0
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