Answer:
The man's total displacement is equal to 0.
Explanation:
Given that,
A man ran a 5 mile race. The race looped around a city park and back to the starting line.
We need to find the total displacement of the man.
We know that,
Displacement = shortest path covered
Also,
Displacement = final position - initial position
As it reaches back to its starting line, it means, the displacement is equal to 0.
Hence, the man's total displacement is equal to 0.
W=mg
a. W=0.01*9.81=0.0981N
b. W=3.6*9.81=35.316N
c.W=0.713*9.81=6.99453N
Explanation:
Electronegativity is the ability of an atom to attract electrons, when it forms a chemical bond in a molecule. However, it is not strictly an atomic property, since it refers to an atom within a molecule. The equivalent property of electronegativity for an isolated atom is electronic affinity.
Answer:
Explanation:
The forward force to drag is 125N
Distance of 3m.
The distance is on the positive horizontal 3i+0j
The force is directed upward so that the horizontal and vertical component is
Fx=107N and Fy=65N
F=107i+65j
Work done is dot product of Force and distance
Then,
W=F.ds
W=(107i+65j).(3i+0j)
Note i.i=j.j=1, i.j=j.i=0
Therefore
W=107×3+65×0
W=321J
The workdone done on the box is 321J
Explanation:
(a) Velocity is given by :
s is the length of the distance
t is the time
The dimension of v will be, ![[v]=[LT^-1]](https://tex.z-dn.net/?f=%5Bv%5D%3D%5BLT%5E-1%5D)
(b) The acceleration is given by :
v is the velocity
t is the time
The dimension of a will be, ![[a]=[LT^{-2}]](https://tex.z-dn.net/?f=%5Ba%5D%3D%5BLT%5E%7B-2%7D%5D)
(c) Since, ![d=\int\limits{v{\cdot}dt} =[LT^{-1}][T]=[L]](https://tex.z-dn.net/?f=d%3D%5Cint%5Climits%7Bv%7B%5Ccdot%7Ddt%7D%20%3D%5BLT%5E%7B-1%7D%5D%5BT%5D%3D%5BL%5D)
(d) Since, ![v=\int\limits{a{\cdot}dt} =[LT^{-2}][T]=[LT^{-1}]](https://tex.z-dn.net/?f=v%3D%5Cint%5Climits%7Ba%7B%5Ccdot%7Ddt%7D%20%3D%5BLT%5E%7B-2%7D%5D%5BT%5D%3D%5BLT%5E%7B-1%7D%5D)
(e)
![\dfrac{da}{dt}=\dfrac{[LT^{-2}]}{[T]}](https://tex.z-dn.net/?f=%5Cdfrac%7Bda%7D%7Bdt%7D%3D%5Cdfrac%7B%5BLT%5E%7B-2%7D%5D%7D%7B%5BT%5D%7D)
![\dfrac{da}{dt}=[LT^{-3}]}](https://tex.z-dn.net/?f=%5Cdfrac%7Bda%7D%7Bdt%7D%3D%5BLT%5E%7B-3%7D%5D%7D)
Hence, this is the required solution.
