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2 years ago

7

I dont need the work, just the answers :)

1 answer:

weqwewe [10]2 years ago

4 0

Distance: sq (-3-(-9))^2 + (-1-8)^2
The answer is square root 117

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What is x?<br> HELP!!<br> Pls

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Since line c and d are parallel, line a can act as a transversal. Thus, x=124 degrees because of the alternate exterior angle relationship that can be seen.

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2 years ago

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A TV is priced at $475.25. There is a 7% sales tax rate. What is the sales tax for the TV in dollars and cents?

Naddik [55]

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3 years ago

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Find the slope of the line that passes through (8, 3) and (1, 9).

leonid [27]

Answer:

$-\frac{6}{7}$

Step-by-step explanation:

⇒ $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

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2 years ago

Is this proportional??

marin [14]

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2 years ago

Suppose that scores on the mathematics part of a test for eighth-grade students follow a Normal distribution with standard devia

riadik2000 [5.3K]

Answer:

We need an SRS of scores of at least 153.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large an SRS of scores must you choose?

This is at least n, in which n is found when $M = 20, \sigma = 150$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$20 = 1.645*\frac{150}{\sqrt{n}}$

$20\sqrt{n} = 1.645*150$

$\sqrt{n} = \frac{1.645*150}{20}$

$\sqrt{n} = 12.3375$

$(\sqrt{n})^{2} = (12.3375)^{2}$

$n = 152.2$

Rounding to the next whole number, 153

We need an SRS of scores of at least 153.

8 0

2 years ago