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bazaltina [42]
2 years ago
10

The coordinates of the vertices of triangle ABC are A(9.-10), B(-15, 0), and C(15, 10). A dilation centered at (0, 0) is perfome

d on triangle ABC to produce triangle ABC. The coordinates of the vertices of triangle A'B'C' are A' (13.5, -15), B(-22.5, OJ, and C(22.5, 15). Find the scale factor. will mark brainlyst ​

Mathematics
1 answer:
Alex2 years ago
8 0
Answer: 1.5 (D)
Explanation: I plotted the points on a graph and calculated the length of AC (20) and A’C’ (30)
The answer should be 30/20 = 1.5
I hope this helps!
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A polynomial function with leading term 8x ^9 has a degree of what?<br>​
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hi! if the leading term is 8x^9, this means that this is the term with the highest power. therefore, its degree is 9.

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Find the value or x. <br> -<br> a. 5 <br> b. 11<br> c. 25<br> d. 31
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If the circumference of a circle is approximately 75.36 meters, what is the area?
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2 years ago
I just need to know the third one pls
katen-ka-za [31]

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98

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4 0
2 years ago
Which expression is equivalent to ( 4mn / m^-2n^6)^-2a. n^6 / 16m^8b. n^10 / 16m^6c. n^10 / 8m^8d. 4m^3 / n^8?
Eva8 [605]

\huge{(} \small{\frac{4mn}{ {m}^{ - 2} {n}^{6}  }}  \huge{) } \small{{}^{  {}^{ {}^{ {}^{ - 2} } } } }\\  \\  \\ \huge{(} \small{   \frac{4 \times m {}^{1}  \times n {}^{1} }{ {m}^{ - 2} \times  {n}^{6}  }}  \huge{)} \small{^{  {}^{ {}^{ {}^{ - 2} } } }} \\  \\  \\  \huge{(} \small{4 \times  {m}^{1 - ( - 2)}  \times  {n}^{1 - 6}} \huge{)} \small{ {}^{  {}^{ {}^{ {}^{ - 2} } } } } \\  \\  \\   \huge{(} \small{ 4 \times  {m}^{1 + 2}  \times  {n}^{ - 5} } \huge{)} \small{ { }^{ {}^{  {}^{  {}^{ - 2} } }  } } \\  \\  \\ \small{  {(4)}^{ - 2} \times  ({m}^{3} ) ^{ - 2} \times  {(n{}^{ - 5} )}^{ - 2}    } \\  \\  \\  \frac{1}{ {4}^{2} }  \times  {m}^{ - 6}  \times  {n}^{ 10}  \\  \\  \\  \frac{1}{16}  \times  \frac{1}{ {m}^{6} }  \times  {n}^{10}  \\  \\  \\  \frac{ {n}^{10} }{16{m}^{6} }







\text{ Hence, option B is correct }
7 0
3 years ago
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