Question

Equation0%3D%20%20-%201" id="TexFormula1" title="(z + \frac{6}{7} ) + \frac{2}{14} = - 1" alt="(z + \frac{6}{7} ) + \frac{2}{14} = - 1" align="absmiddle" class="latex-formula">
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Answer 1

Given:

The equation is

$\left(z+\dfrac{6}{7}\right)+\dfrac{2}{14}=-1$

To find:

The solution of the given equation.

Solution:

We have,

$\left(z+\dfrac{6}{7}\right)+\dfrac{2}{14}=-1$

It can be written as

$\left(z+\dfrac{6}{7}\right)+\dfrac{1}{7}=-1$

$\left(z+\dfrac{6}{7}\right)=-1-\dfrac{1}{7}$

Multiply both sides by 7.

$7z+6=-7-1$

$7z+6=-8$

$7z=-8-6$

$7z=-14$

Divide both sides by 7.

$z=\dfrac{-14}{7}$

$z=-2$

Therefore, the value of z is -2.