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vova2212 [387]
4 years ago
10

Tickets to the concert were $2.50 for adults and $1 for students. $1200 was collected and 750 tickets were sold. Write a system

of linear equations that can be used to find how many adults (a) and how many students (b) attended. How many students attended? (8 points)

Mathematics
2 answers:
PSYCHO15rus [73]4 years ago
7 0

there is  470 adults and kids is 280

fiasKO [112]4 years ago
3 0
Here’s a screenshot of the answer

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Plz help i will mark brainliest
Rama09 [41]

Answer:

22 units

Step-by-step explanation:

The perimeter of a rectangle is 2(width + length)

In this case width = 2z + 2 and length = 3z + 3

replacing everything known:

110 = 2(2z + 2 + 3z + 3)

110/2 = (5z + 5)

55 = 5z + 5

55 - 5 = 5z

50 = 5z

10 = z

Segment PQ is the same as SR = 2z + 2

Replacing z = 10

PQ = 2(10) + 2

8 0
3 years ago
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Which is the following descibes a median of a triangle
Firdavs [7]

According to the internet it states, The median of a triangle is a line segment joining the vertex of the triangle to the mid-point of its opposite side.

It bisects the opposite side, dividing it into two equal parts.

The median of a triangle further divides the triangle into two triangles having the same area

7 0
2 years ago
What kind of math work do I have to write down for the problem -4+(-3)
kifflom [539]

Answer:

-4 + (-3) = -4 - 3 = -7.

Or even: -4 + (-3) = -7.

Step-by-step explanation:

This is a one step problem. It is very straightforward and has very little work.

8 0
3 years ago
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PLEASE HELP ME 50 POINTS!!!!<br><br> Identify an expression that is equivalent to 0.3(15y).
IgorC [24]

Answer: 4.5y

Step-by-step explanation:  You have To Multiply 15 times 0.3 and you get 4.5y

7 0
3 years ago
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If he is correct, what is the probability that the mean of a sample of 68 computers would differ from the population mean by les
elena-14-01-66 [18.8K]

Complete Question

The quality control manager at a computer manufacturing company believes that the mean life of a computer is 91 months with a standard deviation of 10 months if he is correct. what is the probability that the mean of a sample of 68 computers would differ from the population mean by less than 2.08 months? Round your answer to four decimal places. Answer How to enter your answer Tables Keypad

Answer:

P(-1.72

Step-by-step explanation:

From the question we are told that:

Population mean \mu=91

Sample Mean \=x =2.08

Standard Deviation \sigma=10

Sample size n=68

Generally the Probability that The  sample mean  would differ from the population mean

P(|\=x-\mu|<2.08)

From Table

P(|\=x-\mu|

T Test

Z=\frac{\=x-\mu}{\frac{\sigma}{\sqrt{n} } }

Z=\frac{2.08}{\frac{10}{\sqrt{68} } }

Z=1.72

P(|\=x-\mu|

P(-1.72

Therefore From Table

P(-1.72

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3 years ago
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